zerodan: (Default)
[personal profile] zerodan
http://www.think-logically.co.uk/lt.htm

I am pleased that I scored 100% on my first try, though I suspect most (if not all) of you will do the same.

Date: 2009-01-06 09:07 pm (UTC)

That was amusing... now to get picky.

Date: 2009-01-06 09:59 pm (UTC)
From: [identity profile] bitmonger.livejournal.com
I can't decide, but I feel #10 is ambiguous enough to be wrong.

"Paris is in New Zealand." is not the same thing as
"Paris is wholely contained within New Zealand"

So if we answer this as a question posed on set membership (as implied by 'in') we have a problem. (Thus assuming Paris is a set not a element which is also part of the problem here)

As a logic statement:

There exists no x in Paris that is not also in New Zealand.
or
All members of Paris are members of New Zealand

rather than:

There exists an x in Paris in that is also in New Zealand.

Re: That was amusing... now to get picky.

Date: 2009-01-06 10:20 pm (UTC)
From: [identity profile] bitmonger.livejournal.com
The other obvious example is of course something like:

Rome is in Italy.
Rome is in Ohio.

Which we can represent as a graph in a logically constant manner.

Rome
|--> Italy
'--> Ohio

(Ok, I _thought_ I was done being picky... I wasn't)

:)

Re: That was amusing... now to get picky.

Date: 2009-01-07 05:09 am (UTC)
From: [identity profile] frenchpress.livejournal.com
Lol.
So I guess someone didn't get 100%?
;)

Re: That was amusing... now to get picky.

Date: 2009-01-07 10:28 pm (UTC)
From: [identity profile] skyethebard.livejournal.com
I did get 100% but I totally agree that a few of the questions employed assumptions.

Date: 2009-01-07 05:10 am (UTC)
From: [identity profile] frenchpress.livejournal.com
Aargh. I missed the last two. I should have gotten #14 right, but I take issue with #15.

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